7k^2-16=0

Solution for 7k^2-16=0 equation:

7k^2-16=0

a = 7; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·7·(-16)
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{7}}{2*7}=\frac{0-8\sqrt{7}}{14}
=-\frac{8\sqrt{7}}{14}
=-\frac{4\sqrt{7}}{7}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{7}}{2*7}=\frac{0+8\sqrt{7}}{14}
=\frac{8\sqrt{7}}{14}
=\frac{4\sqrt{7}}{7}
$